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Monty Hall Problem
INTERVIEWPUZZLE

Monty Hall Problem

Understand the counterintuitive probability behind the Monty Hall problem and why switching doors improves the odds.

The Monty Hall Problem

The Puzzle: You are on a game show. There are 3 doors:

  • Behind one door is a Car.
  • Behind the other two are Goats. You pick a door (say, Door #1). The host (Monty Hall), who knows what’s behind the doors, opens another door (say, Door #3), which has a goat. He then asks: “Do you want to switch to Door #2?” Is it to your advantage to switch?

1. The Paradox

Most people intuitively think since there are 2 doors left, the probability is 50-50. They are wrong. You should ALWAYS switch.

2. The Math

  1. Initial State: Your door has a 1/3 chance of winning. The other two doors combined have a 2/3 chance.
  2. The Reveal: Monty opens a goat door from the group you didn’t pick.
  3. The Result: The 2/3 probability that was shared by Doors #2 and #3 now “collapses” entirely onto Door #2.
  • Stay: 33.3% chance.
  • Switch: 66.7% chance.

3. Visualization for 100 Doors

Imagine 100 doors. You pick one (1% chance). Monty opens 98 doors that all have goats. Only your door and one other door remain.

  • Do you still think it’s 50-50? Of course not. The other door almost certainly contains the car.

Interview-Focused Questions

Q: Does it matter if the host opens the door randomly?

A: Yes. The puzzle only works because Monty knows where the car is and must open a goat door. If he opened a door randomly and happened to show a goat, switching wouldn’t help.

Q: Why is this puzzle so famous?

A: Because even professional mathematicians famously got it wrong when it was first published. It perfectly demonstrates how our brains are naturally poor at conditional probability.

Key Takeaway

Stay or Switch? Always Switch. You double your chances from 1/3 to 2/3.

My Private Notes

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