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Cuboid Concepts
LOGICALREASONING

Cuboid Concepts

Learn cuboid-based visual reasoning involving dimensions, faces, cuts, painted surfaces, and spatial relationships.

1. Cuboid Dimension Reassembly

What is this?

Small cubes are joined together to make a bigger cube or cuboid.

Questions usually ask:

  • New surface area
  • New volume
  • Surface area lost after joining

Easy Rules

Volume never changes.

Total Volume Before = Total Volume After

Surface area decreases because touching faces become hidden.


Example

Question

Eight unit cubes (1 × 1 × 1) are joined to make one 2 × 2 × 2 cube.

Find

  • New surface area
  • Surface area lost

Step 1: Surface area before joining

Each small cube has

6 faces

Area of one cube

6 × 1² = 6

There are

8 cubes

So

Total Surface Area

= 8 × 6

= 48 square units

Step 2: Make one big cube

The new cube is

2 × 2 × 2

ASCII

      ______
     /_____/|
    /_____/ |
    |     | |
    |     | /
    |_____|/

Surface Area

= 6 × side²

= 6 × 2²

= 6 × 4

= 24 square units

Step 3: Find lost area

Some faces are now inside the cube.

They cannot be seen.

Lost Area

= Old Surface Area

− New Surface Area

= 48 − 24

= 24 square units

Final Answer

New Surface Area = 24

Lost Surface Area = 24

Easy Picture

Before joining

□  □

□  □

□  □

□  □

Every cube has all faces visible.


After joining

      ______
     /_____/|
    /_____/ |
    |     | |
    |     | /
    |_____|/

Many faces touch each other.

Those touching faces disappear from the outside.


Quick Formula

Surface Area

Cube

= 6a²

Volume

Cube

= a³

Lost Area

Old Surface Area



New Surface Area

2. Axis-Based Slicing

What is this?

A cuboid is cut into unit cubes.

Questions ask:

  • Number of cuts
  • Number of cubes formed

Example

A cuboid measures

Length  = 5

Breadth = 3

Height  = 2

Step 1: Draw the cuboid

        __________
       /_________/|
      /_________/ |
      |         | |
      |         | /
      |_________|/

Step 2: Cuts along Length

Length = 5

|----|----|----|----|

5 blocks

Need 4 cuts

Formula

Length − 1

= 5 − 1

= 4

Step 3: Cuts along Breadth

Breadth = 3

|----|----|

3 blocks

Need 2 cuts

Formula

3 − 1

= 2

Step 4: Cuts along Height

Height = 2

|----|

2 blocks

Need 1 cut

Formula

2 − 1

= 1

Step 5: Total Cuts

Length Cuts

+

Breadth Cuts

+

Height Cuts

=

4 + 2 + 1

=

7 cuts

Step 6: Number of Cubes

Multiply all dimensions.

5 × 3 × 2

= 30 cubes

Final Answer

Cuts Needed

= 7

Unit Cubes

= 30

Easy Diagram

Original Cuboid

5 × 3 × 2

After slicing

□□□□□□□□□
□□□□□□□□□
□□□□□□□□□

30 small cubes

Quick Formulas

Number of Cubes

Length × Breadth × Height

Number of Cuts

(Length − 1)

+

(Breadth − 1)

+

(Height − 1)

Shortcut Table

QuestionFormula
Number of unit cubesL × B × H
Cuts along LengthL − 1
Cuts along BreadthB − 1
Cuts along HeightH − 1
Total Cuts(L−1) + (B−1) + (H−1)
Surface Area of Cube6a²
Volume of Cube
Lost Surface AreaOld SA − New SA

Memory Trick

JOINING CUBES
─────────────
✔ Volume stays same
✔ Surface area decreases

CUTTING CUBES
─────────────
✔ Cubes = L × B × H
✔ Cuts = (L−1)+(B−1)+(H−1)

These formulas are enough to solve almost all Cuboid & Cube Reassembly questions in aptitude exams.

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